6(1[v+4]1)=8v+14

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Solution for 6(1[v+4]1)=8v+14 equation:


Simplifying
6(1[v + 4] * 1) = 8v + 14

Reorder the terms:
6(1[4 + v] * 1) = 8v + 14

Reorder the terms for easier multiplication:
6(1 * 1[4 + v]) = 8v + 14

Multiply 1 * 1
6(1[4 + v]) = 8v + 14
6([4 * 1 + v * 1]) = 8v + 14
6([4 + 1v]) = 8v + 14
(4 * 6 + 1v * 6) = 8v + 14
(24 + 6v) = 8v + 14

Reorder the terms:
24 + 6v = 14 + 8v

Solving
24 + 6v = 14 + 8v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-8v' to each side of the equation.
24 + 6v + -8v = 14 + 8v + -8v

Combine like terms: 6v + -8v = -2v
24 + -2v = 14 + 8v + -8v

Combine like terms: 8v + -8v = 0
24 + -2v = 14 + 0
24 + -2v = 14

Add '-24' to each side of the equation.
24 + -24 + -2v = 14 + -24

Combine like terms: 24 + -24 = 0
0 + -2v = 14 + -24
-2v = 14 + -24

Combine like terms: 14 + -24 = -10
-2v = -10

Divide each side by '-2'.
v = 5

Simplifying
v = 5

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